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-5a^2+3a+30=0
a = -5; b = 3; c = +30;
Δ = b2-4ac
Δ = 32-4·(-5)·30
Δ = 609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{609}}{2*-5}=\frac{-3-\sqrt{609}}{-10} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{609}}{2*-5}=\frac{-3+\sqrt{609}}{-10} $
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